Xand y are two positive numbers and y is three greater than x. the product of the numbers is 130. find the smaller number, x.

Xy=130
y=3+x

x(3+x)=130
x²+3x-130=0
(x+13)(x-10)=0
x= -13 or 10

since the question says X and Y are positive we just dismiss-13

x=10
and y=13

The answer is: y would equal 3 because if you simplify the equation then it would be y= 3x+9 and if you divide 3x and 9 by 3 it would equal 3. y= 3