The shortest side of an isosceles triangle is 2x - 3 inches long. the longer sides are 6 inches longer than the shortest side. the perimeter of the triangle is 33 inches. what is the length of each side of the longer sides of the triangle. heeelp mee

Side 1 = short side = 2x-3
side 2 = longer side = (short side) + 6 = (2x-3)+6 = 2x+3
side 3 = side 2 = 2x+3

Side 2 and side 3 are the longer two congruent sides

Add up the three sides and set them equal to the given perimeter of 33. Solve for x

(side1)+(side2)+(side3) = perimeter
(2x-3)+(2x+3)+(2x+3) = 33
(2x+2x+2x) + (-3+3+3) = 33
6x+3 = 33
6x+3-3 = 33-3
6x = 30
6x/6 = 30/6
x = 5

If x = 5, then the longer sides are 2*x+3 = 2*5+3 = 10+3 = 13 inches each
(note: the short side is 2*x-3=2*5-3=10-3 = 7 inches)

13 inches

Jbbfubdibidbidnisbibd