Identify intervals on which the function is increasing, decreasing, or constant. g(x) = 1 - (x - 7)^2

The derivative here is easy enough to find, first expand the equation into:
g(x) = 3 - (x^2 - 10x + 25) = -x^2 + 10x - 22

Take the derivative: g'(x) = -2x +10

Now, we have to find when the equation equals zero. So, we set g'(x) = 0. 0 = -2x + 10, 2x = 10, x = 5. When x is 5, this derivative will be zero, and that is the one and only time when the function is constant. When x is less than 5, you can plug in and see that the derivative will be positive, so the function is increasing when x is less than 5. When x is greater than 5, you can plug in and see that the derivative will be negative, so the function decreasing at x is greater than 5.  Hope  this helped :) have a good day

20y5 times 2 is 1010 times -2 is -20, plus y