Mathematics, 29.07.2019 18:30 robert7248

Evaluate the definite integral. 1/4 csc(2πt) cot(2πt) dt 1/12

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Answer from: candlelight45

$\displaystyle \int\limits^{\frac{1}{4}}_{\frac{1}{12}} {\csc (2\pi t) \cot (2\pi t)} \, dt = \frac{1}{2\pi}$

General Formulas and Concepts:

Calculus

Differentiation

DerivativesDerivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^{\frac{1}{4}}_{\frac{1}{12}} {\csc (2\pi t) \cot (2\pi t)} \, dt$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u: $\displaystyle u = 2\pi t$ [u] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = 2\pi \ dt$ [Bounds] Switch: $\displaystyle \left \{ {{x = \frac{1}{4} ,\ u = 2\pi (\frac{1}{4}) = \frac{\pi}{2}} \atop {x = \frac{1}{12}} ,\ u = 2\pi (\frac{1}{12}) = \frac{\pi}{6}} \right.$

Step 3: integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^{\frac{1}{4}}_{\frac{1}{12}} {\csc (2\pi t) \cot (2\pi t)} \, dt = \frac{1}{2\pi}\int\limits^{\frac{1}{4}}_{\frac{1}{12}} {2\pi \csc (2\pi t) \cot (2\pi t)} \, dt$ [Integral] U-Substitution: $\displaystyle \int\limits^{\frac{1}{4}}_{\frac{1}{12}} {\csc (2\pi t) \cot (2\pi t)} \, dt = \frac{1}{2\pi}\int\limits^{\frac{\pi}{2}}_{\frac{\pi}{6}} {\csc (u) \cot (u)} \, du$ [Integral] Trigonometric Integration: $\displaystyle \int\limits^{\frac{1}{4}}_{\frac{1}{12}} {\csc (2\pi t) \cot (2\pi t)} \, dt = \frac{1}{2\pi}[-\csc (u)] \bigg| \limits^{\frac{\pi}{2}}_{\frac{\pi}{6}}$ Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^{\frac{1}{4}}_{\frac{1}{12}} {\csc (2\pi t) \cot (2\pi t)} \, dt = \frac{1}{2\pi}(1)$ Simplify: $\displaystyle \int\limits^{\frac{1}{4}}_{\frac{1}{12}} {\csc (2\pi t) \cot (2\pi t)} \, dt = \frac{1}{2\pi}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Answer from: Quest

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5

Answer from: Quest

step-by-step explanation:

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Evaluate the definite integral. 1/4 csc(2πt) cot(2πt) dt 1/12...

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