In parallelogram abcd , diagonals ac and bd intersect at point e, be=2x^2−x , and de=x^2+6 . what is bd ?

BE = DE

2x^2-x = x^2+6

x^2-x-6 =0

(x+2) (x-3)

x = -2 or x = 3

1 solution using x = -2:

BE = 2(-2)^2 -(-2) = 10

DE = (-2)^2+6 = 10

10 +10 =20

2nd solution using x = 3

BE =2(3)^2-3 = 15

DE = (3)^2+6 =15

15+15 = 30

 The answer could be 20 or 30. Will need to try them both

 Would probably try 30 first ( maybe x can't be a negative number?)

for a it would be 24 children.

for b i don't understand the question. is it saying for each individual person they pick 5 reds to 7 greens or is it the whole group. clarify and i hope this can you.

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)