Aparticle moves with velocity function v(t) = 2t2 - 3t - 3, with v measured in feet per second and t measured in seconds. find the acceleration of the particle at time t = 2 seconds. (4 points) a. 3/4 ft/s^2 b. -1 ft/s^2 c. 32ft/s^2 d. 5 ft/s^2

d. 5 ft/s^2

Step-by-step explanation:

The acceleration is the derivative of the velocity.

In this problem, we have the velocity function

So the acceleration function is:

.

Find the acceleration of the particle at time t = 2 seconds

This is a(2). So:

.

The correct answer is

d. 5 ft/s^2

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

definition: a circle is the  set of all points in a plane that are equidistant  from a given  point  called the center of the circle. we use the symbol ⊙ to represent a circle. the a line segment from the center of the circle to  any point  on the circle is a radius of the circle.

step-by-step explanation:

i googled it and this is what i got i don't know how it is. sorry.