Can someone me on this asap

in the figure k> 0.

(a) is abc pqr? support your answer with a theorem or postulate.

(b) how does the area of pqr compare to the area of abc? justify your answer.

(a) Yes, Δ ABC and ΔPQR are similar triangles.

(b) Ratio of the areas of ΔPQR and ΔABC will be k².

Step-by-step explanation:

In the figure attached two triangles, Δ ABC and Δ PQR have been given.

(a).In these triangle ∠ABC ≈ ∠PQR, ∠ACB ≈ ∠PRQ (Given)

Since it is given that two angles of the given triangles are equal so third angle will also be equal.

So by the theorem AAA both the triangles will be similar.

(b). Since in two similar triangles corresponding sides are in the same ratio (By theorem of similar triangles)

Therefore, sides of Δ PQR and Δ ABC will be in the same ratio = k where k > 1

Now area of Δ ABC A=

Similarly area of Δ PQR =

Now ratio of area of Δ PQR and Δ ABC

So ratio of area of Δ PQR and Δ ABC will be k².

step-by-step explanation: