What is the probability that you will get a 3-digit combination correct if no digits in the combination can be repeated? 1/10 1/504 1/720

The probability that you will get a 3-digit combination correct is:

   1/720

Step-by-step explanation:

We are asked to find the probability that you will get a 3-digit combination correct if no digits in the combination can be repeated.

Now the favorable number of outcomes=1 (which is the correct combination)

Total number of outcomes=  10×9×8

(first place has 10 choices of digits from 0-9 ,second has 9 choices excluding the one at first place and third place has 8 choice)

                                           =720

Probability= number of favorable outcomes/total number of outcomes

                 =  1/720

i dont know sorry

step-by-step explanation:

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11