Mathematics, 27.07.2019 21:00 aweller3898
Find the sine, cosine, and tangent of 120 degrees. (5 points) sin 120 degrees = square root of 3 divided by 2, cos 120 degrees = negative 1 divided by 2, tan 120 degrees = negative square root of 3 sin 120 degrees = negative 1 divided by 2, cos 120 degrees = square root of 3 divided by 2, tan 120 degrees = negative square root of 3 sin 120 degrees = square root of 3 divided by 2, cos 120 degrees = 1 divided by 2, tan 120 degrees = square root of 3 sin 120 degrees = square root of 3 divided by 2, cos 120 degrees = negative 1 divided by 2, tan 120 degrees = negative square root of 3
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