Scores on a standardized test are normally distributed with a mean of 350 and a standard deviation of 25. approximately what percent of students scored between 360 and 380?

22.95 %

Step-by-step explanation:

Given : Scores on a standardized test are normally distributed with

Mean :

Standard deviation :

The formula to find z-score:-

For x=360

For x=380

The p-value =

In percent , the percent of students scored between 360 and 380 =

0.85 or 85%

step-by-step explanation:

1) divide 23 by 27

2) round the decimal to the nearest 10

3) so your answer would be 0.85 or 85%

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.