Identify the triangle that contains an acute angle for which the sine and cosine ratios are equal.

we have to consider a triangle whose acute angle measure is 45° so that the sine and cosine ratios are equal.

Step-by-step explanation:

We need to consider a right angled triangle such that the measure of one of angle is 90° ,the second angle is 45° and hence the third angle could be found by using the fact that the sum of all the angles is 180°.

Hence we get the third angle measure to be 45°

( ∠1+∠2+∠3=180°

90+45+∠3=180

∠3=180-(90+45)

∠3=45° )

so in the right angled triangle if we use our trignometric identity along either angle 2 or angle 3 we get;

sin 45°=

and cos 45°=  

Hence the sine and cosine angle are equal.

So we have to consider a triangle whose acute angle measure is 45° so that the sine and cosine ratios are equal.

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.