Patsy has cheerleading practice every fourth day. she wants to be in the school play, but they have practice every sixth day. if both start on september 5th, what would be the next date she has to choose between cheerleading and play practice? show your work and explain. the one to do so will be marked brainiest and will be

The next date that should be choose is 17.

Given that,

Based on the above information, the calculation is as follows:

Days of cheerleading practice should be 5,9,13,17,21,25,29...

Days of school play should be 5,11,17,23,29...

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Step-by-step explanation:

To get the answer we just have to sum the days beginning in September 5th. We know that cheerleading practices are every fourth day, and school play is every sixth day. So, we need to sum this days and see when they will match.

5, 9, 13, 17, 21, 25, 29...

5, 11, 17, 23, 29...

So, basically, the first day when Patsy will be able to do only one activity is on September 17th, she will have both activities the same day. The second day this will happen would be September 29th.

my acc plz

step-by-step explanation:

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )