Dg, eg, and fg are perpendicular bisectors of the sides of △ abc . dg=5 centimeters and bd=12 centimeters.

what is cg ?

enter your answer in the box.

- CG= 13 cm

Explanation:-

Given : Δ ABC where DG, EG, and FG are perpendicular bisectors of the sides intersecting at point G .

⇒ G is the circumcenter of the triangle.

⇒BG, CG and AG are the angle bisectors of the triangle.

Now, from the given figure

In ΔBDG and ΔBEG

∠D = ∠ E [right angle]

BG=BG [reflexive property]

∠DBG=∠EBG [Definition of angle bisector]

⇒ΔBDG ≅ ΔBEG [AAS congruence theorem]

Thus BD=BE= 12 cm [CPCT]

DG=EG= 5 cm [CPCT]  .....(1)

Now In ΔBGE and ΔCGE

GE=GE  [reflexive property]

∠BEG=∠CEG  [right angle]

BE=EC [Definition of perpendicular bisector]

⇒ΔBGE ≅ ΔCGE [SAS postulate]

⇒BE=CE=12 cm ......(from (1))

and GE= 5 cm

As ΔCGE is right angle then by Pythagoras theorem,

x

step-by-step explanation:

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841