Triangle abc and triangle cde are similar right triangles. which proportion can be used to show that the slope of ac is equal to the slope of ce?

a)
3 − 5
−4 − 0
=
3 − 2
0 − 2

b)
3 − 5
−4 − 0
=
3 − 2
2 − 0

c)
5 − 3
−4 − 0
=
3 − 2
0 − 2

d)
5 − 3
−4 − 0
=
2 − 3
0 − 2

The proportion (5-3) / (-4-0) = (3-2) / (0-2) can be used to show that the slope of AC in triangle ABC is equal to the slope of CE in triangle CDE, where these triangles are similar right triangles.

Option C) (5-3) / (-4-0) = (3-2) / (0-2)

Solution

Slope of AC: mac=(ya-yc)/(xa-xc)

A=(-4,5)=(xa,ya)→xa=-4, ya=5

C=(0,3)=(xc,yc)→xc=0, yc=3

mac=(5-3)/(-4-0)

Slope of CE: mce=(yc-ye)/(xc-xe)

C=(0,3)=(xc,yc)→xc=0, yc=3

E=(2,2)=(xe,ye)→xe=2, ye=2

mce=(3-2)/(0-2)

mac=mce

(5-3) / (-4-0) = (3-2) / (0-2)

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p