Find a polynomial of degree 2 with real number coefficients and zero 3-2i

Complex roots occur as conjugates so the other root is 3 + 2i

so we have  the factored form 

(x - (3 - 2i)(x - (3 + 2i)

= (x - 3 + 2i)(x - 3 - 2i)

= x^2 -3x - 2ix - 3x + 9 + 6i + 2ix - 6i- 4i^2

=  x^2 -6x + 9 + 4

= x^2 - 6x + 13   Answer