Given: abc and fgh are right angles; ba||gf; bc ≅ gh prove: abc ≅ fgh step 1: we know that abc ≅ fgh because all right angles are congruent. step 2: we know that bac ≅ gfh because corresponding angles of parallel lines are congruent. step 3: we know that bc ≅ gh because it is given. step 4: abc ≅ fgh because of the

Step-by-step explanation:

Given: ΔABC and ΔFGH are right angles, BA||GF; BC ≅ GH.

To prove: ΔABC ≅ ΔFGH

Proof:

Step 1. ∠ABC ≅ ∠FGH  (Because  all right angles are congruent)

Step 2.  ∠BAC ≅ ∠GFH (Because corresponding angles of parallel lines are congruent)

Step 3. BC ≅ GH (Given)

Step 4. From  ΔABC and  ΔFGH

∠ABC ≅ ∠FGH

    BC ≅ GH

∠BAC ≅ ∠GFH

thus, by ASA rule of congruency, ΔABC ≅ ΔFGH.

70

step-by-step explanation:

2*5=10

4*15=60

60+10=

70