What is the vertex of the parabola. assume p> 0

The emphasis and the equidistant from the vertex but on opposite sides. As the focus is at (0, p) and the directrix has the equation y = -p then its nearest point to the vertex is at (0,-p) and thus the vertex is at the origin (0,0). The parabola is balanced about the y axis. The normal calculation for a parabola opening up with its vertex at the origin is, x² = 4cy where c is the distance from the vertex to the focus. Reorganizing the original equation gives: - y = ¼px²: x² = 4(1/p) y . . . but this would mean that the distance from the vertex to the focus is (1/p).  So the parabola equation must be y = ¼(1/p) x² or (1/4p) x² and thus x² = 4py

two data sets with the same median will not have the same varaibility

step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet