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Mathematics, 23.07.2019 20:10 chenepiernas

Find the equation for the line tangent to the parametric curve: xy==t3βˆ’25t25t2βˆ’t4 x=t3βˆ’25ty=25t2βˆ’t4 at the points where t=5t=5 and t=βˆ’5t=βˆ’5. for t=5t=5, the tangent line (in form y=mx+by=mx+b) is

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Find the equation for the line tangent to the parametric curve: xy==t3βˆ’25t25t2βˆ’t4 x=t3βˆ’25ty=25t2βˆ’t4...
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