Abag of assorted candy contains 11 peppermints, 8 chocolates, 13 gumdrops, and 9 licorices. amy randomly takes a gumdrop from the bag and eats it. what is the probability that the next candy she takes from the bag will be a gumdrop or a peppermint?

We can calculate the probability of an event by finding the number of ways the event can occur and dividing by the total number of possible outcomes. Let's find the number of ways Amy can choose a gumdrop or a peppermint. After one gumdrop is removed from the bag, the number of gumdrops or peppermints remaining is 12 + 11 which is 23. Amy has 23 ways to choose a gumdrop or a peppermint. Let's find the total number of possible outcomes. After one gumdrop is removed, the number of candies remaining is 11+8+12+9 which is 40. The probability that Amy takes a gumdrop or a peppermint next is 23/40 which is 57.5%

Answer:

13.46

step-by-step explanation:

16.80 x .20 = 13.46