What are the coordinates of the midpoint of ef if point e is located at (–12, 5) and point f is located at (7, –9)? (-5/2,7) (5/2,7) (-5/2,-2) (5/2,-2)

The midpoint of a segment divides the segment into equal halves.

The coordinates of the midpoint EF is (c) (-5/2,-2)

The coordinates are given as:

The midpoint (m) is calculated using

So, we have:

Simplify

Divide -4 by 2

Hence, the coordinates of the midpoint is (c) (-5/2,-2)

Read more about midpoints at:

link

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

hi there! my name is zalgo and i am here to you out today. the answer is pretty simple (in a way). this equation equals to 25.2!

i hope this answer !

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