Is the relationship shown by the data linear? if so, model the data with an equation. x y 1 –4 7 –7 13 –10 19 –13

Yes, the relationship shown by the data linear.

The equation is given by:

The table of values is given by:

           x            y

           1            -4

           7            -7

           13          -10

           19          -13

We know that the difference in each of the x-value is: 6

( Since, 7-1=6

13-7=6

19-13=6)

and if the difference in the each of the y-value is same then the relationship is linear.

( Since, a table of values represent a linear relationship if the rate of change is constant.

i.e. the ratio of change in y-values to the change in x-values)

Hence, we find the difference in y-value:

-7-(-4)= -3

-10-(-7)= -3

-13-(-10)= -3

Since, the difference in y-value is constant.

             Hence, the relationship is linear.

Also, we know that the equation of the line will pass through (1,-4) and (7,-7)

Hence, the equation of line is calculated by:

answer: can you show the options ?

step-by-step explanation:

ending amount = beginning amount / (2^n)

where "n" = number of half-lives (or elapsed time / half-life)

ending amount = 50 mg / (2 ^10 / 5.3)

ending amount = 50 mg / (2 ^ 1.8867924528)

ending amount = 50 m / 3.6981210597

ending amount = 13.5203794557 mg

or about 13.5 mg remain

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