Asquare hamburger is centered on circular bun, both have an area of 16 square inches. how far, to the naerest hundredth of an inch, does each corner of the burger stick out from the bun?

The solution:

 For the bread:

Area = π R²
  
16 in² = π R²

R² = 16 in² / π

Bun radius = √(16 in² / π)  =  2.257 inches

For the meat:

Area = side²

16 in² = side²

Side =  √16 in²  =  4 inches

Diagonal of the square = 4 √2  =  5.657 inches

1/2 of the burgerdiagonal = 2.828 inches .

If the meat is placed on the center of the bun, then the corner of the burger
extends to: (2.828 - 2.257)  =  0.57 inch

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

0 = ( 2 - 4 ) ( p + q )0 = ( 2 - 4 ) ( 2 + 5 i ),   by multiplying these0 = ( 4 + 10 i - 8 - 20 i )0 = 4 - 8 + 10 i - 20 i0 = - 4 -10 i   0 = 2 ( - 2 - 5 i )0 / 2 = - 2 - 5 i- 2 - 5 i = 0- 5 i = 2i = 2 / - 5

The answer would be a