Aperson at ground level measures the angle of elevation to the top of a building to be 74 degrees. if at this point the person is 34 feet away from the base of the building, then how tall is the building? ( round to the tenths place; show work/steps and provide units with your answer) will give brainiest

to find the height of the building multiply the distance ( 34 feet) by the tangent of the angle(74)

34 * tan(74) = 118.57 feet

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )

130 degrees. i have no other way to explain