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![\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad \sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\ -------------------------------\\\\ \left( \sqrt[3]{2^5} \right)^{\frac{1}{4}}\implies \left( 2^{\frac{5}{3}} \right)^{\frac{1}{4}}\implies 2^{\frac{5}{3}\cdot \frac{1}{4}}\implies 2^{\frac{5}{12}}](/tpl/images/0116/6048/b9945.png)
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