The path of a flying fish as it made its approach to the surface of the ocean and flew out of the water is represented by the quadratic function h(t) = -t2 + 6t - 5, where t represents the time, in seconds, and h(t) represents the fish's height and depth, in feet. graph the function using the graphing calculator. to the nearest second, how long was the fish out of the water?

Your best bet would be to graph   h(t) = -t^2 + 6t - 5, either on paper or on your graphing calculator.  The graph will have the shape of an upside-down parabola.  You need to estimate, from the graph, the values of t at which h(t) = 0.  Alternatively, you could calculate them by setting 

h(t) = -t^2 + 6t - 5 = to  0.

Estimate the distance between those two points (roots), to answer the last question.

How might I help you further?  Please try this graphing and ask if you have questions about how to do this.

1935/10,000= 387/2000the answer to the question is c