An article reported that for a sample of 41 kitchens with gas cooking appliances monitored during a one-week period, the sample mean co2 level (ppm) was 654.16, and the sample standard deviation was 165.74. (a) calculate and interpret a 95% (two-sided) confidence interval for true average co2 level in the population of all homes from which the sample was selected. (round your answers to two decimal places.)

Given:

Mean of 654.16

Sample size is 41

Standard dev is 165.74

Alpha is 1 – 0.95, Z(0.025) = 1.96

So the computation would be:

Mean ± Z* s/sqrt (n)

= 654.16 ± 1.96*165.74/sqrt(41)

= 654.16 ± 1.96*25.88

= 654.16 ± 50.7248

= 603.4352, 704.8848 is the confidence interval

Interpretation: We are 95% confident that this confidence interval contains the true pop. mean

step-by-step explanation:

4  

25

5258y

54.

t5

5r

54

5856

542

5458

86

.8558.65

565

565

55898

786

8/95

5896

8656265

556478

this is a good question! i’ll do some research and what i find, i’ll contact you asap when i have something! ✊