Accomplished silver workers in india can pound silver into incredibly thin sheets, as thin as 3.00 10-7 m (about one-hundredth of the thickness of a sheet of paper). find the area of such a sheet that can be formed from 2.90 kg of silver.

The density of silver is 10,500 kg/m^3, therefore the volume of a 2.90 kg silver is:

V = 2.90 kg / (10,500 kg/m^3)

V = 0.000276 m^3

We know that volume is simply area times height:

Volume = Area * height

SO the area is:

Area = 0.000276 m^3 / 3.00 x 10-7 m

Area = 920.63 m^2

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answer is because 4×10=40

and 98×4= is 392

40,392