Wyatt’s eye-level height is 120 ft above sea level, and shawn’s eye-level height is 270 ft above sea level. how much farther can shawn see to the horizon? use the formula mc024-1.jpg, mc024-2.jpg with d being the distance they can see in miles and h being their eye-level height in feet.

Using the formula given: d = √(3h/2)

We simply substitute the given values of h into the equation and compare the results.

For Wyatt where h = 120:
d = √(3(120)/2)
d = 13.42 miles

For Shawn where h = 270:
d = √(3(270)/2)
d = 20.12 miles

Since the question asks for how much farther can Shawn see, we subtract the results:

20.12 - 13.42 = 6.7

Therefore, Shawn can see 6.7 miles farther.

With a continuous thought process.