what is the area of a rectangle with vertices at (−4, 0) , (−3, 1) , (0, −2) , and (−1, −3) ? enter your answer in the box. do not round any side lengths.

If we plot the points, we can see which 2 points create the length and the width. Using the distance formula, we can compute for the dimensions.

width = sqrt [(-4 - -3)^2 + (0 – 1)^2] = sqrt (2)

length = sqrt [(-3 - 0)^2 + (1 – -2)^2] = sqrt (18)

Therefore the area is:

Area = length * width

Area = sqrt (2) * sqrt (18)

Area = 6

125 yards

step-by-step explanation:

i take 75 plus 50.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)