Hexagon defghi is translated 8 units down and 3 units to the right. if the coordinates of the pre-image of point f are (–9, 2), what are the coordinates of f'?

f' = (-6, -6)

step-by-step explanation:

the coordinate specifying vertical position is the y-coordinate. when a point is moved 8 units down, 8 is subtracted from the value of the y-coordinate. 2 - 8 = -6.

the coordinate specifying the horizontal position is the x-coordinate. when a point is moved 3 units to the right, 3 is added to the x-coordinate. -9 +3 = -6.

the image coordinates are:

f' = f + (3, -8) = (-9+3, 2-8)

f' = (-6, -6)

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

51

step-by-step explanation:

73-22=51 the   mass number minus the amount of protons gives you the amount of neutrons