Aballoon is released from the top of a platform that is 50 meters tall. the balloon rises at the rate of 4 meters per second. write an equation in slope-intercept form that tells the height of the balloon above the ground after a given number of seconds.

Slow intercept form is y = mx + b

y = dependent variable = height of balloon (h)
x = independent variable = time (t)
m = slope = rise of balloon height with respect to time of 4 m/s
b = y-intercept = initial height of 50m

thus, putting it all together, we get . . .

h = (4 m/s)t + (50m)

Dwould be the answer

1. 0.3 •4 is the same as 4 groups of 0.32. 7•0.8 is the same as 7 groups of 0.83. it increases by 0.5 every time, so 0.5x4 it increases by 0.9 every time, so 0.9x5. 0.9•12=10.86. 0.47•5=2.35i can finish the next ones in a separate post