Atoy rocket is shot vertically into the air from a launching pad 5 feel above the ground with an initial velocity of 80 feet per second. the height h, in feet, of the rocket above the ground as t seconds after launch is given by the function h(t)=-16t^2+80t+5. how long will it take the rocket to reach its maximum height? what is the maximum height?
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For this case we have the following function:

To find the time when it reaches its maximum height, what we must do is to derive the function.

We have then:

We set zero and clear the time:

Then, we evaluate the time obtained for the function of the height.

We have then:

It will take the rocket to reach its maximum height:

the maximum height is:

he spend 5.1 minutes chatting with his friends

step-by-step explanation:

2/5+1/2=9/10

6/1-9/10=5 1/10

$450

step-by-step explanation:

first, you have to multiply 150x2=300

next, you have to add 150+300= 450