What is the equation of a line that passes through the point (8, −2) and is parallel to the line whose equation is 3x + 4y = 15? enter your answer in the box

I'll include mt steps in case you need or want them. Quick note: remember that y=mx+b, and m is slope, and b is the y-intercept.
1. Subtract 3x from each side:
4y=15-3x
2. Divide both sides by 4:
y=(15/4)+(-3x/4)
3. Now you have the slope of your line (-3/4), but you still need to find the y-intercept, so you'll need to use y=mx+b.
y=(-3x/4)+b
4. Plug in the values from the point given and solve to find b.
-2=((-3×8)/4)+b
-2=(-24/4)+b
-2=-6+b
4=b
5. Write the equation using your values for the slope and y-intercept. So your final answer should be:
y=(-3x/4)+4

Hope this helped