Abox of marbles can be shared equally among 6,7,or 8 students with 4 marbles left over each time. what is the least possible number of marbles in the box?

If there are 4 marbles left over each time, then we can forget about them for now.

So the question is, what is the smallest number than can be divided into 6,7 and 8?

the numbers have only one non-1 divisor in common: both 6 and 8 are divisible by 3.

so for our purposes we can "delete" one 2 and ask:

what is the smallest number than can be divided into 3,7 and 8 ?

There are no more divisors in common, so we just have to multiply them: 3*7*8=21*8=168

and the 4 marbles "extra"? We add them to this sum.

the the smallest possible number in the box is 168+4=172.

The answer is 3. parallelogram

The academic affairs council is the highest expert body processing academic affairs, as stipulated by the university statutes. specialist aaro häkkinen (educational policy) took part in the council’s meeting. the agenda of the meeting included bachelors’ feedback, the timing of pedagogical studies, the grant system for tuition fees, the standardisation of administrative practices for internships and the situation of foreign-language and multilingual master’s programmes.