The coordinates of the vertices of△jkl are j(−5,−1), k (0,1), and l(2,−5).is △jkl a right triangle?

we know that

The formula to calculate the slope between two points is equal to

we have

Step 1

Find the slope of the side JK

substitute the values in the formula

Step 2

Find the slope of the side KL

substitute the values in the formula

Step 3

Find the slope of the side JL

substitute the values in the formula

Step 4  

Verify if triangle JKL is a right triangle

we know that

if two lines are perpendicular, then the product of their slopes is equal to minus one

so

a) compare slope JK with slope KL

we have

-------> the side JK and side KL are not perpendicular

b) compare slope KL with slope JL

we have

-------> the side KL and side JL are not perpendicular

c) compare slope JK with slope JL

we have

-------> the side JK and side JL are not perpendicular

therefore

the answer is

The triangle JKL is not a right triangle

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

126 maybe. sorry