How do i find the equation of a line passing through the given point and parallel to the given equation of (3,4) and y = -7/5× -3

I think you meant, "How do I find the equation of a line passing through the given point and parallel to the given equation?:    (3,4) and y = -(7/5)× -3

Two parallel lines have the same slope.  The slope of the given line is -7/5.
The new line passes thru (3,4).  Use the point-slope formula for a str. line:

y-4 = (-7/5)(x-3)    (answer)

This could be written in other forms if desired, e. g., the slope-intercept form.

So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.