The vertices of δabc are (-2,0), (-2, 3), and (-5, 1). t(x, y) = (x + 1, 3y) represents the transformation of the triangle. what are the coordinates of the vertices for δa'b'c'? are the pre-image and image congruent? justify your answer.

using the equation for the transformation:

(x+1, 3y)

 add 1 to very X and multiply y by 3

 so (-2,0) becomes (-1,0)

(-2,3) becomes (-1,9)

(-5,1) becomes (-4,3)

new coordinates are (-1,0) (-1,9) (-4,3)

you don't have an image attached, so to see if they are congruent, the sides need to stay the same lengths and the angles need to stay the same, from the coordinates of the new triangle, I would say they are not congruent