For a physics experiment, students toss a basketball in the air from the top of a school building. they write the expression y=-16x^2+48x+56 to represent the hight, in feet, of the basketball after x seconds. based on the expression, what is the hight, in feet, of the school building?

Move all terms to one sidey+16{x}^{2}-48x-56=0y+16x​2​​ −48x−56=02 use the quadratic formulahow? x=\frac{48+8\sqrt{92-y}}{32},\frac{48-8\sqrt{92-y}}{32}x=​32​​48+8√​92−y​​​ ​​ ,​32​​48−8√​92−y​​​ ​​ 3 simplify solutionsx=\frac{6+\sqrt{92-y}}{4},\frac{6-\sqrt{92-y}}{4}x=​4​​6+√​92−y​​​ ​​ ,​4​​6−√​92−y​​​ ​​