Three zeroes of a fifth degree polynomial function are 1/3, 4-6i and -2 +11i. determine the remaining zeroes of the function.

Answer is option A

Step-by-step explanation:

Given that  there is a fifth degree polynomial. The three zeroes are given as

1/3, 4-6i, -2+11i

Since the polynomial having real coefficients will have imaginary roots occurring in conjugates only we can say that the imaginary roots will have conjugates also as zeroes of the polynomial.

We have one real root 1/3.

The imaginary roots are 4-6i and -2+11i

Hence these conjugates will be zeroes

i.e. are the other zeroes

Option A is right.

goog may have it for you

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50