Use technology and the given confidence level and sample data to find the confidence interval for the population mean muμ. assume that the population does not exhibit a normal distribution. weight lost on a diet: weight lost on a diet: 99 % confidence 99% confidence n equals 61n=61 x overbar equals 2.0 kgx=2.0 kg s equals 4.8 kg

The given in this problem are:

99% confidence level

N = 61

Mean = 2.0 kg

Standard deviation = 4.8

Z value for a 9% confidence interval is 2.576

Confidence Interval = mean ± Z s/ sqrt n

= 2.0 ± 2.576(4.8/sqrt 61)

=2.0 ± 2.576 (0.6145770236779006736364371988794)

= 2.0 ± 1.5832

= 0.4168 < x < 3.5832

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!