What is the area of a parallelogram whose vertices are a(−12, 2) , b(6, 2) , c(−2, −3) , and d(−20, −3) ? enter your answer in the box.

To solve this, we simply have to get the length and the width. Based from the graph, we can see that the length is connected by 2 points (-12, 2) and (6, 2) or (-20, -3) and (-2, -3). The height between the two lengths is 5 which can be counted manually.

We use the distance formula to calculate the length from either pair of points.

length^2 = [(-12 – 6)^2 + (2 – 2)^2]

length = 18

Therefore the area is:

Area = length * height

Area = 18 * 5

Area = 90

step-by-step explanation: the answer is 27. first multiply .32 by 25 which equals 8. then add 8 to 25 which gives you 33. then you subtract that from 6 since she gave 6 to her brother.

,, add !