Abcd is a rectangle with ac=20 and ab=2bc. what is the area of rectangle abcd?

Let AB = 2x and BC be x.

By pythagoras theorum,

20² = x² + (2x)²

400 = x² + 4x²
400 = 5x²
80 = x²

x= √80 = 4√5 , thus, 2x = 8√5

Now, area = AB x AC

= 4√5 * 8√5

= 32 * 5

= 160

Thus, the area of rectangle ABCD is 160 units

Atranslation 6 units to the right and 4 down