Find the volume of the solid that lies under the hyperbolic paraboloid z = 4 + x 2 − y 2 and and above the square r = [−1, 1] × [0, 2].

The volume of the solid under the hyperbolic paraboloid and above the square r = [−1, 1] × [0, 2] is

The question is asking us to find the volume bounded by the following surfaces

To do this, we have to evaluate the triple integral

First, we integrate with respect to

Next, we integrate with respect to

Finally, we integrate with respect to

The volume of the solid is

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f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.