How do i solve x=y+8
and 5x+3y=12in substitution form

x = 4.5 and y = -3.5

Step-by-step explanation:

To find the solution to this system of equations using the substitution method, you must solve for either the x or y variable and then substitute into the other equation.

x = (y + 8)

5x + 3y = 12

We will use the first equation to solve for x. The x has to be isolated on one side. Since the first equation already has x on the one side, we can plug it into the other equation.

5(y+8) + 3y = 12

Distribute and solve:

5y + 40 + 3y = 12

8y + 40 = 12

8y = 12-40

8y = -28

y = -3.5

Now we have the y variable, we can plug that back into the first equation to find x.

x = (-3.5) + 8

x= 4.5

Your answer will be x = 4.5 and y = -3.5

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

the answer is simply just 6n add the two together as they have an n