Nia has a number cards for 2,3,8,9,5.what are all the different ways nia can arrange the cards to show only even numbers with the 2 in the ten-thousands place?

1.       Nia has 2, 3, 8, 9 and 5 in her cards. How can she arrange it to be an even numbers with the 2 in the ten thousands place.
Now, Nia has 5 cards, that means, the biggest value she can have is ten thousands which is stated to be 2.
=> 20 000
=> We still have 3, 8, 9 and 5
=>  Let’s have 3 thousands, which is also an even number
=> let’s have 5 as hundreds, also an even number
=> We can have 9 tens, which is also an even number
=> and last is 8 ones, which is also an even number
Thus, the number will be:
=> 23 598, this is an even number because it can be divide by 2
=> 11 799
 

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12