Write a complete two-column proof for following information. given: ab = 3y - 1, bc = 7y, ac = 29 prove: ab = 8 its a normal line and the letters are in order abc, b is kinda close to a

A, B, and C are 3 collinear point. (3 points on the same line.)

AB=3y-1, and BC=7y

Since A, B, and C then AC = AB+BC = (3y-1)+7y = 10y-1

AC is 29 units, so we write the equation:

(AC=) 10y-1 =29

adding 1 to both sides, we have:
          
               10y=30, 

dividing both sides by 10:
 
                    y=3.

AB = 3y-1, substituting y with 3, we have AB=3*3-1=9-1=8

Dwould be the answer