Find an equation of a line perpendicular to -2x + 5y = -10 passing through (-2,10).

-2x + 5y = -10
5y = 2x - 10
y = 2/5x - 2...slope here is 2/5. A perpendicular line will have a negative reciprocal slope. All that means if flip the original slope and change the sign. So our perpendicular line will have a slope of -5/2.

y = mx + b
slope(m) = - 5/2
(-2,10)...x = -2 and y = 10
now we sub into our formula and solve for b, the y int
10 = -5/2(-2) + b
10 = 5 + b
10 - 5 = b
5 = b

so ur perpendicular equation is : y = -5/2x + 5

Is there a picture because i cannot answer it sorry