What is the equation of a line that is parallel to 2x+3y=3 and passes through the point (3, −4) ? enter your answer in the box.

3y=-2x+3
y=-2/3x+3/3
y=-2/3x+1
compare y=mx+c
m=-2/3
for parallelism m=M
so M=-2/3

now eqn for (3,-4)
is given by y-(-4)/x-3 = -2/3
y+4/x-3=-2/3
3(y+4)=-2(x-3)
3y+12=-2x+6
3y+2x+12-6=0
3y+2x+6=0
or
3y+2x=-6

Ithink it would be 160 people