Aflag in the shape of a right triangle is hung over the side of a building as shown below. the total weight of the flag is 250 pounds and it has uniform density. a = 15 and b = 39.

(a) The density of flag is Pounds per square foot

(b) The weight of strip is Pounds

(c) The work is foot-pounds

(d) The exact work by roof is 1250 foot-pounds

Step-by-step explanation:

(a) We are given a flag in the shape of a right triangle.

The total weight of flag is 250 pounds and Uniform density.

Base of the flag

Area of the flag

Weight of flag = 250 pounds

Hence, The density of flag is

(b) Weight of strip which is h feet below the roof.

Length of strip

Width of strip

Weight = Density x area

Hence, The weight of strip is

(c) Work slice to move h feet above to the roof

work

Hence, The work is foot-pounds

(d) Exact work on the roof by hanging flag

Hence, The exact work by roof is 1250 foot-pounds

3201

step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length