Atriangle has an area of 24 square meters. the base is two meters longer that the height. what is the length of the base of the triangle?

base = h + 2
height = h
A = 1/2bh
(1/2)h(h + 2) = 24
(1/2)(h^2 + 2h) = 24
2(1/2)(h^2 + 2h) = 2(24)
h^2 + 2h = 48
h^2 + 2h - 48 = 48 - 48
h^2 + 2h - 48 = 0
factor:
(h + 8)(h - 6) = 0
h + 8 = 0
h + 8 - 8 = -8
h = -8
h - 6 = 0
h - 6 + 6 = 6
h = 6
you can not have a negative value so h = 6
check:
(1/2)(6(6 + 2)) = 24
(1/2)(6(8)) = 24
(1/2)48 = 24
24 = 24

Hope this helps

~From a fellow middle schooler

a right triangle. and in the future use this desmos.com to you

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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